0=-4.9x^2+10x+443

Solution for 0=-4.9x^2+10x+443 equation:

0=-4.9x^2+10x+443

We move all terms to the left:

0-(-4.9x^2+10x+443)=0

We add all the numbers together, and all the variables

-(-4.9x^2+10x+443)=0

We get rid of parentheses

4.9x^2-10x-443=0

a = 4.9; b = -10; c = -443;
Δ = b2-4ac
Δ = -102-4·4.9·(-443)
Δ = 8782.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-\sqrt{8782.8}}{2*4.9}=\frac{10-\sqrt{8782.8}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+\sqrt{8782.8}}{2*4.9}=\frac{10+\sqrt{8782.8}}{9.8}
$